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a 1507kg truck enters a corner with a radius of 465m with a centripetal force magnitude of 3410n. What is the truck’s speed?

Respuesta :

Chelboy

Answer:32.44m/s

Explanation:

Centripetal force=(mass(velocity)^2)/r

3410=(1507v^2)/465

Cross product

3410×465=1507v^2

1585650=1507v^2

V^2=1585650/1507

V^2=1052.189781

V=√(1052.189781)

V=32.44joules

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