Answer:
(3) 34.5grammes of C2H6O
(4) 5.56 x 10^22 Formula units
(5) 0.5 moles of CaCO3
Explanation:
(3) molar mass of C2H6O = 24 + 6 + 16 = 46 g/mol
mass of C2H6O =0.75 mole x 46 g/mole = 34.5 grammes
(4) Formula units of NaCl = (5.4/ 58.5) x 6.022x10^23 = 5.56 x 10^22
(4) moles = mass / molar mass
molar mass of CaCO3 = 40 + 12 + 48 = 100 g/mol
moles of CaCO3 = 50/100 = 0.5 moles
