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A 0.34 kg ball is attached to the end of a cord of length 1.1 m. The ball is whirled in a circular path in a horizontal plane. The cord can withstand a maximum tension of 51.1 N before it breaks. What is the maximum speed the ball can have without the cord breaking?

Respuesta :

fredycopete

Answer:

12.86 m/s

Step-by-step explanation:

Centripetal acceleartion formula:

[tex]F=m.(\frac{v^{2} }{r})\\[/tex]

[tex]v=\sqrt{(\frac{F.r}{m}) }\\[/tex]

[tex]v = \sqrt{\frac{51.1 N * 1.1 m}{0.34 kg} } \\[/tex]

[tex]v = 12.86 \frac{m}{s\\}\\[/tex]

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