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By simultaneously conserving energy and momentum, calculate the energy of the neutron emitted in the forward direction by a beam of 150 keV deuterons undergoing the D-T reaction in a tritium target.

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akande212

Answer: 2372Kev

Eg = 2222keV

Eex = ?

Eex - Eg = 150keV

Eex - 2222 = 150

Eex = 150 + 2222

Eex = 2372keV

Explanation:

The energy possessed by the deuterium particles in their ground state or unexcited state is Eg and in that in their excited state is Eex

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