Answer:
The distance from B to B' is 5 units
Step-by-step explanation:
we know that
A translation is a rigid transformation, that means, the size and the shape of the pre-image is the same that the size and the shape of the image after the translation
so
The distance AA' will be equal to the distance BB'
the formula to calculate the distance between two points is equal to
[tex]d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}[/tex]
we have
A(1,5) and A'(-2,1)
substitute
[tex]d=\sqrt{(1-5)^{2}+(-2-1)^{2}}[/tex]
[tex]d=\sqrt{(-4)^{2}+(-3)^{2}}[/tex]
[tex]d=\sqrt{25}[/tex]
[tex]d=5\ units[/tex]
therefore
The distance from B to B' is 5 units
