Answer:
4.55 mol of C₂H₂
Explanation:
Let's verify the reaction:
CaC₂ + 2H₂O → C₂H₂ + Ca(OH)₂
Ratio is 1:1, so 1 mol of calcium carbide will produce 1 mol of acetylene.
4.55 mol of CaC₂ will make the same amount of C₂H₂
Answer:
There will be produced 4.55 moles C2H2 ( this is 118.48 grams)
Explanation:
Step 1: Data given
Number of moles CaC2 = 4.55 moles
water is in excess
Molar mass of CaC2 = 64.1 g/mol
Molar mass of acetylene = 26.04 g/mol
Step 2: The balanced equation
CaC2 + 2H2O → C2H2 + Ca(OH)2
Step 3: Calculate moles of C2H2
For 1 mol CaC2 we need 2 moles of H2O to produce 1 mol of C2H2 and 1 mol of Ca(OH)2
For 4.55 moles of CaC2 we'll have 4.55 moles C2H2
Mass C2H2 = 4.55 moles C2H2 *26.04 g/mol = 118.48 grams
There will be produced 4.55 moles C2H2 ( this is 118.48 grams)
