Answer:
The product will be propanoic acid .
Explanation:
Under the action of strong oxidizing agent that is potassium dichromate in an acidic medium primary oxidizes the primary alcohols into carboxylic acid .
[tex]RCH_2OH+K_2Cr_2O_7\overset{H^+}\rightarrow RCOOH+H_2O[/tex]
So, when propanol is treated with potassium dichromate in an acidic medium it get converted into propanoic acid.
[tex]CH_3-CH_2-CH_2-OH+K_2Cr_2O_7\overset{H^+}\rightarrow CH_3-CH_2-COOH+H_2O[/tex]
