Answer:
12.9 g potatoes
Explanation:
Given data:
Amount of heat used = 3.54 Kj
Initial temperature = 25°C
Final temperature = 100°C
Specific heat capacity of potatoes = 3.67 j/g.°C
Solution:
Formula:
Q = m.c. ΔT
Q = amount of heat absorbed or released
m = mass of given substance
c = specific heat capacity of substance
ΔT = change in temperature
ΔT = T2 - T1
ΔT = 100°C - 25°C
ΔT = 75°C
Q = m.c. ΔT
m = Q / c. ΔT
m = 3540 j / 3.67 j/g.°C × 75°C
m = 3540 j / 275.25 j/g
m = 12.9 g
