A 3.00 kg toy falls from a height of 1.00 m. What will the kinetic energy of the toy be just before the toy hits the ground? (Assume no air resistance and that g = 9.81 m/s656-06-03-00-00_files/i0090000.jpg.)

Respuesta :

Kinetic energy formula: Ek = m · v² / 2
We have: m= 3 kg,  v= ?
h= g·t²/2 ,     t²= 2h/g = 2 m / 9.81 m/s² = 0.2 s² ,  t=√0.2(sqrt)= 0.45 s
v= g· t = 9.81 m/s² · 0.45 s = 4.43 m/s
Finally: Ek=[tex] \frac{m v^{2} }{2} = \frac{3 kg * (4.43 m/s)^{2} }{2} = \frac{58.87 J}{2} [/tex]= 29.43 J