[tex] \frac{1}{2} (x+12)=4x-1[/tex]
Multiply both sides by 2 :
[tex] \frac{1}{2}(x+12)*2 = 4x*2-1*2 [/tex]
[tex]x+12=8x-2[/tex]
[tex]x+12-12=8x-2-12[/tex]
[tex]x=8x-14[/tex]
Subtract 8 x from both sides:
[tex]x-8x=8x-14-8x[/tex]
[tex]-7x=-14[/tex]
Divide both sides by -7 :
[tex] \frac{-7x}{-7} = \frac{-14}{7} [/tex]
[tex]x = \frac{14}{7} [/tex]
[tex]x = 2[/tex]
1 solution
hope this helps!
