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(x^2-9)/(x+1) ÷ (x^2-6x+9)/(7x+7) reduced form?

A) 7(x-3)^2 B) 7(x+3) C) 7(x-3) D) 7(x+3)^2
----------- --------- ---------- ------------
x+3 x-3 x+3 x-3

Respuesta :

caylus
Hello,

[tex] \dfrac{\dfrac{x^2-9}{x+1}}{\dfrac{x^2-6x+9}{7x+7}}=7*\dfrac{(x-3)(x+3)*(x+1)}{(x+1)(x-3)^2}=7*\dfrac{x+3}{x-3} [/tex]