Respuesta :
e = mc^2
m = e / c^2
Plug in your numbers in the appropriate units.
m=1.02 × 10^-5
m = e / c^2
Plug in your numbers in the appropriate units.
m=1.02 × 10^-5
Answer : The amount of mass in kilograms lost would be, [tex]1.022\times 10^{-2}Kg[/tex]
Solution : Given,
Energy of released in the reaction = [tex]9.20\times 10^{11}KJ[/tex]
Speed of light = c = [tex]3\times 10^8m/s[/tex]
Formula used :
[tex]E=m\times c^2[/tex]
where,
E = energy released
m = mass
c = speed of light
Now put all the given values in the above formula, we get the amount of mass would have been lost.
[tex]9.20\times 10^{11}KJ=m\times (3\times 10^8m/s)^2[/tex]
[tex]m=1.022\times 10^{-5}KJ/m^2s^{-2}=1.022\times 10^{-5}\times 10^3Kg=1.022\times 10^{-2}Kg[/tex]
conversion : [tex](1KJ/Kg=10^3m^2/s^2)[/tex]
Therefore, the amount of mass in kilograms lost would be, [tex]1.022\times 10^{-2}Kg[/tex]