Respuesta :
The problem applies Charles' law since constant pressure with varying volume and temperature are given. Assuming ideal gas law, the equation to be used is [tex] \frac{ V_{1} }{ T_{1} } [/tex]=[tex] \frac{ V_{2} }{ T_{2} } [/tex]. We make sure the temperatures are expressed in Kelvin, hence the given added with 273. The volume 2 is equal to 25.2881 liters.
Answer: The volume at [tex]100.0^0C[/tex] is 25.3 L
Explanation:
To calculate the final volume of the system, we use the equation given by Charles' Law. This law states that volume of the gas is directly proportional to the temperature of the gas at constant pressure.
Mathematically,
[tex]\frac{V_1}{T_1}=\frac{V_2}{T_2}[/tex]
where,
[tex]V_1\text{ and }T_1[/tex] are the initial volume and temperature of the gas.
[tex]V_2\text{ and }T_2[/tex] are the final volume and temperature of the gas.
We are given:
[tex]V_1=20.0L\\T_1=22.0^oC=(22.0+273)K=295.0K\\V_2=?\\T_2=100.0^oC=(100.0+273)K=373.0K[/tex]
Putting values in above equation, we get:
[tex]\frac{20.0}{295.0K}=\frac{V_2}{373.0}\\\\V_2=25.3L[/tex]
The volume at [tex]100.0^0C[/tex] is 25.3 L
