pH of the potasium hydroxide solution = 9.61
Explanation:
When potasium hydroxide (KOH) is dissolved in water the following dissolution takes place:
KOH (s) → K⁺ (aq) + OH⁻ (aq)
where:
(s) - solid
(aq) - aquous
Because KOH is a strong base, the concentration of [KOH] is equal to the concentration [OH⁻].
[KOH] = [OH⁻] = 0.000243 M
We also know that
[OH⁻] × [H₃O⁺] = 10⁻¹⁴
[H₃O⁺] = 10⁻¹⁴ / [OH⁻]
[H₃O⁺] = 10⁻¹⁴ / 0.000243
[H₃O⁺] = 2.43 × 10⁻¹⁰ M
And to find the pH of the solution:
pH = -lg[H₃O⁺]
pH = -lg[2.43 × 10⁻¹⁰]
pH = 9.61
Learn more about:
pH
https://brainly.com/question/1525823
https://brainly.com/question/12678552
#learnwithBrainly
