The equation of line that is parallel to y=6x+3 and goes through the point (1,-4) is: [tex]y = 6x-10[/tex]
Step-by-step explanation:
Given equation of line is:
[tex]y = 6x+3[/tex]
Let m1 be the slope of given line.
As the equation of line is in slope-interept form, the coefficient of x is the slope of the line
So,
m1 = 6
Let m2 be the slope of line parallel to given line
then
m2 = 6
As parallel lines have equal slopes
Slope-intercept form of equation is given by:
[tex]y = m_2x+b[/tex]
Putting the value of slope
[tex]y = 6x+b[/tex]
Putting (1,-4) in the equation
[tex]-4 = 6(1)+b\\-4 = 6+b\\b = -4-6\\b = -10[/tex]
Putting the value of b in equation
[tex]y = 6x-10[/tex]
Hence,
The equation of line that is parallel to y=6x+3 and goes through the point (1,-4) is: [tex]y = 6x-10[/tex]
Keywords: Equation of line, slope-intercept form
Learn more about equation of line at:
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