Seudónimo Seudónimo
  • 15-12-2019
  • Mathematics
contestada

how do you completely factor 4k^2+14k+12?
please help me with the steps!

Respuesta :

kalsoomtahir1 kalsoomtahir1
  • 15-12-2019

Answer:

4k^2+14k+12 =(4k+6)(k+2)= 2(2k+3)(k+2)

Step-by-step explanation:

[tex]4k^2+14k+12[/tex]

[tex]4k^2+8k+6k+12[/tex]

4k(k+2) + 6(k+2)

(4k+6)(k+2)

2(2k+3)(k+2)is solution set

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