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Rob is two times as old as Jake. Three years ago the sum of their ages was 21 years. Find their present ages?

Respuesta :

Rob is 18
Jake is 9

21-15=6
6+3=9
9x2=18
(No clue how I got 15 )

Suppose Rob's age is X and Jake's age Y

Since Rob is two times as old as Jake, X = 2Y

Since Three Years ago the sum of their ages was 21,

X + Y = 21 + 6 This is true because it was three years ago, so they both got older by 3 years

You plug in X to the second equation to fin 2Y + Y = 21 + 6 which is 3Y = 27, so Y = 7 Then, you plug this into the first equation and find that X = 14

So Rob is 14 and Jake is 7

Hope this helps :)

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