Respuesta :
Answer:
The final temperature of water is 20.5061 °C.
Explanation:
Let the final temperature of water be 'x'.
Given:
Heat added to water is, [tex]Q_{in}=12.15\ J[/tex]
Initial temperature of water is, [tex]T=20.5\ \°C[/tex]
Mass of water is, [tex]m=475\ g[/tex]
Now, heat is added to water and its temperature is increased. The temperature is increased because water absorbs all the heat.
Heat absorbed by water is given as:
[tex]Q_{abs}=mc(x-T)[/tex] where 'c' is specific heat capacity of water and its value is equal to 4.186 J/g °C.
Now, plug in the given values and simplify.
[tex]Q_{abs}=475\times4.186\times(x-20.5)\\Q_{abs}=1988.35(x-20.5)[/tex]
Now, from law of conservation of energy, we know that:
Heat absorbed by water = Heat added to water
[tex]Q_{abs}=Q_{in}\\1988.35(x-20.5)=12.15\\x-20.5=\frac{12.15}{1988.35}\\x-20.5=0.0061\\x=20.5+0.0061=20.5061\ \°C[/tex]
So, the final temperature of water is 20.5061 °C.
