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The perimeter of a rectangular field is 284 m.
If the length of the field is 76 m, what is its width?
Width of the field:
m

Respuesta :

msroro1801

Answer: Perimeter of a rectangle is 2 times the length plus 2 times the width.  That makes our equation-

2L + 2W = P    

Fill in what we know for the width and perimeter for W and P, and we get-

2L + 2(64) = 284

Now solve for L

2L + 2(64) = 284          

2L + 128 = 284           simplify by multiplying 2(64)

     -128    -128           subtract 128 from both sides of the equation

2L           = 156

    2L/2   = 156/2        divide both sides of the equation by 2

        L    =    78

The length of the parking lot is 78 meters!

Check your answer-

2(78) + 2(64) = 284

    156 + 128 = 284

              284 = 284

We now know we have the correct answer!

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