Answer:
3) OPTION 4
4) OPTION 1
Step-by-step explanation:
3) Mean is the usual average.
Here, the data is: 60, 74, 82, 87, 87, 94.
Mean = [tex]$ \frac{60 + 74 + 82 + 87 + 87 + 94}{6} $[/tex]
[tex]$ = \frac{484}{6} $[/tex] = 80.667
Median: For even number of terms, Median = [tex]$ \frac{ (\frac{n}{2})^{th} \hspace{2mm}term + (\frac{n}{2} + 1)^{th} \hspace{2mm} term}{2} $[/tex]
Before using the formula we arrange the data in the size of increasing order.
[tex]$ \implies 60, 74, 82, 87, 87, 94 $[/tex]
So, since there are even terms here, [tex]$ (\frac{n}{2})^{th}$[/tex] term is 82 and [tex]$ (\frac{n}{2} + 1)^{th} $[/tex] term is 87, we have,
Median = [tex]$ \frac{82 + 87}{2} $[/tex]
= 84.5
Mode is the value with highest frequency in the data.
Here, 87 has occurred with frequency 2.
Therefore, Mode = 87
4) Data: 5, 5, 7, 7, 6
Mean = [tex]$ \frac{5 + 5 + 7 + 7+ 6}{5} $[/tex]
= 6
Median: When the data set has odd numbers. It is the center term.
After arranging the terms in increasing order, the center term is 6.
So, Median = 6.
Mode: Terms with high frequency.
Here, both 5 and 7 occur with frequency 2, Mode = 5, 7.
