Answer:
Option d) is correct
Step-by-step explanation:
T is a point at a given distance on the unit circle from P(0,1) .
Clearly, the point P(0,1) lies on the circle itself .
To find: the quadrant in which T lies
Given: angle at which point T lies is [tex]\frac{11\pi}{6}[/tex].
Solution :
[tex]\frac{11\pi}{6}=\frac{11\times 180^{\circ}}{6}=11\times 30^{\circ}=330^{\circ}[/tex]
As [tex]270^{\circ}< 330^{\circ}< 360^{\circ}[/tex],
So, basically we are talking about the fourth quadrant as angle [tex]330^{\circ}[/tex] lies in the fourth quadrant .
Therefore, point T lies in quadrant IV.
i.e If T is the point at the given distance on the unit circle C from P (1, 0), then T lies in the IV quadrant.
So, option d) is correct .
