Answer:
x = -{(1+2y)}/2
Step-by-step explanation:
We have used the intercept form of the line.
Step-by-step explanation:
[tex]\huge\blue{\underline{\underline{\bf question}}}[/tex]
Find equation of above line!
[tex]\huge\blue{\underline{\underline{\bf answer}}}[/tex]
Here we can easily observe that=>
The line is passing from two points
(4, -2) and (0, -1)
So it's slope will be given by=>
[tex]m = \frac{y2 - y1}{x2 - x1} \\ \\ m = \frac{ - 1 - ( - 2)}{0 - 4} \\ \\ m = \frac{ - 1}{4} [/tex]
So by using slope point form we'll get =>
[tex](y - 0) = m(x - ( - 1)) \\ y = \frac{ - 1}{4} (x + 1) \\ \\ 4y = - x - 1 \\ \\ \leadsto \boxed{x + 4y + 1 = 0}[/tex]
