Answer:
POINTS OF INTERSECTION ARE:
x = -1
y = 3
coordinates : (-1,3)
Coordinates :
Explanation:
Condition for intersecting lines
[tex]\frac{a_{1}}{a_{2}}\neq\frac{b_{1}}{b_{2}} [/tex]
here
a1 ,a2 = coefficients of x (a1 = -1 , a2 = 6)
b1 ,b2 = coefficients of y(b1 = 1 , b2 = 1)
[tex]frac{-1}{6}\neq\frac{1}{1}\neq\frac{1}{1} [/tex]
Calculation :
Here substitution method is used : Value of y from eq (1) is substitued in equation (2)
-x + y = 4
y = 4 + x.............(i)
put value of x in equation (2)
6x + y = -3
6x + 4 + x = -3 ( from i)
7x = -3 - 4
7x = -7
x = [tex]frac{-7}{7}[/tex]
x = -1
using equation(i)
y = 4 + (-1)
y = 4 - 1
y = 3
Check:
The values of x and y should satisfy equation (1) and (2)
for equation 1
-x+y =4
= -(-1) + 3
= 1 + 3
= 4
Hence coordinates satisfy equation 1
