A 21.7kg child descends a slide 3.5 m high and reaches the bottom with a speed of 2.2m/s. How much thermal energy due to friction was generated in this process?

Respuesta :

Answer:

Subtract the kinetic energy at the bottom from the potential energy loss. The remainder becomes frictional heat.

Potential energy loss:

M g H = 21.7*9.81*3.5 = 745.1 J

Kinetic energy at bottom of slide:

= (1/2) M v^2 = 52.5 J

Frictional heat generates when two surfaces slide against each other. The heat generated due to the friction in the given process is 6.92.7 J.

Frictional heat:

This heat is generated when two surfaces slide against each other.

Potential energy :  

[tex]U = m g h \\[/tex]

Put the values

[tex]U = 21.7\times 9.81\times 3.5 \\\\U = 745.1\rm \ J[/tex]

The Kinetic energy in the bottom:

[tex]K = \dfrac 12m v^2 \\\\K = 52.5 J[/tex]

So the friction heat,

[tex]H_f = U- K\\\\H_f = 745.2 - 52.5 \\\\H_f = 692.7 \rm J[/tex]

Therefore, the heat generated due to the friction in the given process is 6.92.7 J.

learn more about frictional heat.

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