Answer:
Explanation:
[tex]C_i=3.7\times 10^{16} \,decays/sec[/tex]
Energy of gamma rays due to ore decay is
[tex](1.17+1.33)MeV=2.50MeV[/tex]
Energy of gamma ray produced in seconds is
[tex](2.5\times 3.7\times 10^{16})MeV[/tex]
Activity
[tex]1 \times 10^6c[/tex]
Total energy of gamma ray produced in second is
[tex] (2.5 \times 3.7 \times 10^{16} \times 10^6)MeV[/tex]
E-energy of gamma ray produced in an hour is
[tex] (2.5\times 3.7\times 10^{10}\times 60 \times 60)MeV[/tex]
Gamma ray energy absorbed by meat = 30% (in 1 hour) of E is 0.3E
Dose required to kill pathogen = 4000Gy=4000J/kg
The kilogram of meat that can be produced per hour is
[tex]\frac{0.3E/hr}{4000J/kg}\\\\E=(2.5\times 3.7\times 10^{10}\times 60 \times 60)MeV\\\\=333\times 10^{18}MeV\\\\eV=1.6\times 10^{-19}\\\\E=53.3J[/tex]
The meat that can be produced =[tex]\frac{0.3\times 53.3}{4000}=3.996\times 10^{-3}[/tex]
