Answer:
The amount of energy required to increase temperature 275°C to 385°C is ΔQ =3.95208kJ
Explanation:
Given :
- The mass of the water vapour is 18 g
- The initial temperature : 275°C
- The final temperature : 385°C
According to the formula :
Δ[tex]Q = m*s*[/tex]Δ[tex]T[/tex]
Where ,
- Δ[tex]Q[/tex] is the heat supplied
- [tex]m[/tex] is the mass of the substance (water vapour) = 18g
- [tex]s[/tex] is the specific heat of the substance ( water vapour) = [tex]1.996Jg^{-1}K^{-1}[/tex]
- Δ[tex]T[/tex] is the change in temperature =[tex]385-275=110K[/tex]
∴
ΔQ = [tex]18*1.996*110\\=3952.08J[/tex]
⇒ΔQ =3.95208kJ
