Answer:
[tex](\frac{x+5}{3}) ^{2}+ (\frac{y-8}{7} )^{2} =1[/tex]
Step-by-step explanation:
- IMPORTANT FORMULA: the standard equation of a hyperbola whose transverse axis is parallel to the y axis is:
[tex](\frac{x-h}{a}) ^{2}+ (\frac{y-k}{b} )^{2} =1[/tex]
where, (h,k) : center of the hyperbola
a : semi conjugate axis [ length of conjugate axis/2]
b: semi transverse axis [ length of transverse axis/2]
- so, here a=3, b=7, [h,k]=[-5,8]
- by substituting these values in the above given formula,
- the equation of the hyperbola in standard form is :
[tex](\frac{x-(-5)}{3}) ^{2}+ (\frac{y-8}{7} )^{2} =1[/tex]
[tex](\frac{x+5}{3}) ^{2}+ (\frac{y-8}{7} )^{2} =1[/tex]
