The charges for mowing lawns are $5 per hour and charges for walking dogs are $3 per hour.
Step-by-step explanation:
Let,
x be the charge per hour for mowing lawns
y be the charge per hour for walking dogs
According to given statement;
10x+4y=62 Eqn 1
8x+5y=55 Eqn 2
Multiplying Eqn 1 by 5
[tex]5(10x+4y=62)\\50x+20y=310\ \ \ Eqn\ 3[/tex]
Multiplying Eqn 2 by 4
[tex]4(8x+5y=55)\\32x+20y=220\ \ \ Eqn\ 4\\[/tex]
Subtracting Eqn 4 from Eqn 3
[tex](50x+20y)-(32x+20y)=310-220\\50x+20y-32x-20y=90\\18x=90[/tex]
Dividing both sides by 18
[tex]\frac{18x}{18}=\frac{90}{18}\\x=5[/tex]
Putting in Eqn 1
[tex]10(5)+4y=62\\50+4y=62\\4y=62-50\\4y=12[/tex]
Dividing both sides by 4
[tex]\frac{4y}{4}=\frac{12}{4}\\y=3[/tex]
The charges for mowing lawns are $5 per hour and charges for walking dogs are $3 per hour.
Keywords: linear equation, subtraction
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