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A trumpet player is tuning his instrument by playing an A note simultaneously with the first-chair trumpeter, who has perfect pitch. The first-chair player's note is exactly 440 Hz, and 2.70 beats per second are heard. Part A What are the two possible frequencies of the other player's note? Express your answers in hertz separated by a comma.

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Answer:

The two possible frequencies of the other player's note are  437.3 Hz and 442.7 Hz

Explanation:

Given Data

f₁=440 Hz

fₐ=2.7 beats per seconds

The beat frequency is equal to the difference in the frequencies of the two original waves:

So

f =|(f₁±fₐ)|

First to Solve for (-) Sign we get

f=|(440-2.7)|

f=437.3 Hz

Now for Solve for (+) Sign we get

f=|(440+2.7)|

f=442.7 Hz

The two possible frequencies of the other player's note are  437.3 Hz and 442.7 Hz

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