Answer:
Velocity = 5.47[m/s]
Explanation:
Using one of the equations given (kinematic equation), we can find the initial velocity or the takeoff speed at which Michael Jordan can jump.
[tex]v_{x} ^{2} =v_{x0} ^{2}+2*a*(x-x_{0} ) \\where:\\v_{x}= final velocity [m/s]\\v_{x0}=initial velocity or takeoff velocity [m/s]\\a= acceleration = 10 [m/s^2]\\x = final displacement [m]x_{0} = initial displacement [m][/tex]
In this particular case we need to stablish the conditions:
1) Vx = 0 (because when Michael Jordan reach the highest elevation his velocity will be zero
2) x = 1.5 [m] (maximum elevation reached by Michael Jordan)
3) X0= 0[m] (When Jordan has his feet on the ground]
Now replacing the values:
[tex]0^{2}=v_{0}^{2} -2*(10)*(1.5-0)\\v_{0}=\sqrt{2*10*(1.5)} \\v_{0}=5.47[m/s][/tex]
Note: we take acceleration with minus sign because acceleration is action down
