Answer:
The system of Equations are [tex]\left \{ {{0.25q+0.1d=6.80} \atop {d=3q}} \right.[/tex]
Step-by-step explanation:
Given:
Let the number of dimes be d.
Also let the number of quarters be q.
Total Money = $6.80
Ted has $6.80 in quarters and dimes.
Hence the equation can be framed as;
[tex]0.25q+0.1d=6.80 \ \ \ \ equation \ 1[/tex]
Now also given:
The number of dimes is 3 times the number of quarters.
Hence above statement can be framed as;
[tex]d=3q[/tex]
Hence The system of Equations are [tex]\left \{ {{0.25q+0.1d=6.80} \atop {d=3q}} \right.[/tex]
