Answer:
The velocity at the top of its path will be zero (0)
Explanation:
We can solve this problem or particular situation using the principle of energy conservation.
Which tells us that energy is transformed from kinetic energy to potential energy and vice versa. A reference point should be considered at which the potential energy is zero, and at this point the initial velocity of 40 [m/s] is printed to the ball.
[tex]Ek=Ep\\where:\\Ek=kinetic energy [J]\\Ep=potencial energy [J][/tex]
The potential energy is determined by:
[tex]Ep=m*g*h\\where:\\m=mass of the ball[kg}\\g=gravity[m/s^2]\\h=heigth [m]\\[/tex]
The kinetic energy is determined by:
[tex]Ek=\frac{1}{2}*m*v_{0} ^{2} \\where\\v_{0} = initial velocity[m/s][/tex]
[tex]Ek=Ep\\\frac{1}{2} *m*v_{0} ^{2} =m*9.81*h\\h=\frac{40^{2}}{2*9.81} \\h=81.5[m][/tex]
This will be the maximum path but, its velocity at this point will be zero. Because now all the kinetic energy has been transformed in potential energy.
