Answer:[tex]T=12.69^{\circ}C[/tex]
Explanation:
Given
Mass of ice [tex]m=60 gm[/tex]
mass of water [tex]M=760 gm[/tex]
Initial Temperature of water [tex]T_i=20^{\circ}C[/tex]
Let T be the Final Temperature of mixture
Latent heat of Fusion [tex]L=334 J/gm[/tex]
heat required to melt ice completely is
[tex]Q_1=60\times 334=20.04 kJ[/tex]
Heat released by water is taken by ice thus
[tex]Mc_{water}(20-T)=mL+mc_{water}(T-0)[/tex]
[tex]0.76\times 4.184\cdot (20-T)=20.04+0.06\times 4.184\cdot (T)[/tex]
[tex]T=12.69^{\circ}C[/tex]
