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A 1423-kg car is moving along a level highway with a speed of 26.4 m/s. The driver takes the foot off the accelerator and the car experiences a slowing force of 901-N over a distance of 106 m. Determine the speed of the car after traveling this distance.

Respuesta :

Answer:

Final speed, v = 28.81 m/s

Explanation:

Given that,

Mass of the car, m = 1423 kg

Initial speed of the car, u = 26.4 m/s

Force experience by the car, F = 901 N

Distance, d = 106 m

To find,

The speed of the car after traveling this distance.

Solution,

The force experienced by a car is equal to the product of mass and acceleration.

[tex]F=ma[/tex]

[tex]a=\dfrac{F}{m}[/tex]

[tex]a=\dfrac{901}{1423}[/tex]

[tex]a=0.63\ m/s^2[/tex]

Let v is the final speed of the car. Using third equation of motion to find it as :

[tex]v^2-u^2=2ad[/tex]

[tex]v^2=2ad+u^2[/tex]

[tex]v^2=2\times 0.63\times 106+(26.4)^2[/tex]

v = 28.81 m/s

So, the final speed of the car is 28.81 m/s.