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The coefficient of the restitution of an object is defined as the ratio of its outgoing to incoming speed when the object collides with a rigid surface. For an object with a coefficient of 0.72, what fraction of the object's kinetic energy is lost during a single collision?

Respuesta :

usmanbiu

Answer:

48.16 %

Explanation:

coefficient of restitution = 0.72

let the incoming speed be = u

let the outgoing speed be = v

kinetic energy = 0.5 x mass x [tex] x velocity^{2}[/tex]

  • incoming kinetic energy = 0.5 x m x [tex]x u^{2}[/tex]

     

  •  coefficient of restitution =[tex]\frac{v}{u}[/tex]

       0.72 =[tex]\frac{v}{u}[/tex]

       v = 0.72u

        therefore the outgoing kinetic energy = 0.5 x m x [tex](0.72u)^{2}[/tex]

        outgoing kinetic energy = 0.5 x m x [tex]0.5184 x u^{2}[/tex]

        outgoing kinetic energy = 0.5184 (0.5 x m x [tex]x u^{2}[/tex])

recall that 0.5 x m x [tex]x u^{2}[/tex] is our incoming kinetic energy, therefore

outgoing kinetic energy = 0.5184 x (incoming kinetic energy)

from the above we can see that the outgoing kinetic energy is 51.84 % of the incoming kinetic energy.

The energy lost would be 100 - 51.84 = 48.16 %

samueladesida43

The fraction of the object's kinetic energy is lost during a single collision is 48.16%.

HOW TO CALCULATE COEFFICIENT OF RESTITUTION?

According to this question;

  1. Coefficient of restitution = 0.72
  2. Incoming speed = u
  3. Outgoing speed = v

kinetic energy = 0.5 x mass x v²

incoming kinetic energy = 0.5 x m x v²

Coefficient of restitution = v/u =

0.72 = v/u

v = 0.72u

Outgoing kinetic energy = 0.5 x m x 0.72²

Outgoing kinetic energy = 0.5 x m x 0.5184

Outgoing kinetic energy = 0.5184 (0.5 x m x )

0.5 x m x x² is the incoming kinetic energy

outgoing kinetic energy = 0.5184 x (incoming kinetic energy)

It can be observed from the above that the outgoing kinetic energy is 51.84% of the incoming kinetic energy.

The energy lost would be 100 - 51.84 = 48.16 %

Therefore, the fraction of the object's kinetic energy is lost during a single collision is 48.16%.

Learn more about coefficient of restitution at: https://brainly.com/question/999862

samueladesida43

The fraction of the object's kinetic energy is lost during a single collision is 48.16%.

HOW TO CALCULATE COEFFICIENT OF RESTITUTION?

According to this question;

Coefficient of restitution = 0.72

Incoming speed = u

Outgoing speed = v

kinetic energy = 0.5 x mass x v²

incoming kinetic energy = 0.5 x m x v²

Coefficient of restitution = v/u =

0.72 = v/u

v = 0.72u

Outgoing kinetic energy = 0.5 x m x 0.72²

Outgoing kinetic energy = 0.5 x m x 0.5184

Outgoing kinetic energy = 0.5184 (0.5 x m x )

0.5 x m x x² is the incoming kinetic energy

outgoing kinetic energy = 0.5184 x (incoming kinetic energy)

It can be observed from the above that the outgoing kinetic energy is 51.84% of the incoming kinetic energy.

The energy lost would be 100 - 51.84 = 48.16 %

Therefore, the fraction of the object's kinetic energy is lost during a single collision is 48.16%.

Learn more about coefficient of restitution at:

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