contestada

The position (in radians) of a car traveling around a curve is described by Θ (t) = t 3 - 2t 2 - 4t + 10 where t (in seconds). What is the angular acceleration at t = 5 s?The position (in radians) of a car traveling around a curve is described by Θ (t) = t 3 - 2t 2 - 4t + 10 where t (in seconds). What is the angular acceleration at t = 5 s?'

Respuesta :

Answer:[tex]\alpha =30-4=26 rad/s^2[/tex]

Explanation:

Given

Position of a car is  given by

[tex]\theta =t^3-2t^2-4t+10[/tex]

and angular speed is [tex]\frac{\mathrm{d} \theta }{\mathrm{d} t}=\omega [/tex]

angular acceleration is

[tex]\frac{\mathrm{d^2} \theta }{\mathrm{d} t^2}=\alpha [/tex]

[tex]\alpha =6t-4[/tex]

at [tex]t=5 s[/tex]

[tex]\alpha =30-4=26 rad/s^2[/tex]

Otras preguntas