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Which of the following changes will always increase the efficiency of a thermodynamic engine? Choose all correct statements.

Check all that apply.
A. Decrease the hot reservoir temperature TH while keeping the cool reservoir temperature TC constant.
B. Increase the difference TH−TC.
C. Decrease the ratio TC/TH.
D. Increase TH while keeping TC constant. Increase TC while keeping TH constant. Decrease TC while keeping TH constant.

Respuesta :

Answer:B,C,D

Explanation:

Thermodynamic  efficiency is given by

[tex]\eta =1-\frac{T_C}{T-H}[/tex]

[tex]\eta [/tex] efficiency can be increased by Keeping [tex]_c[/tex] constant and increasing [tex]T_H[/tex]

Keeping [tex]T_H[/tex] constant and decreasing [tex]T_c[/tex]

by increasing [tex]\Delta T=T_H-T_c[/tex]

by decreasing [tex]\frac{T_C}{T_H}[/tex] ratio          

Answer:

option (c)

Explanation:

The efficiency of the engine is given by

[tex]\eta =1-\frac{T_{c}}{T_{H}}[/tex]

to increase the efficiency of the engine, the temperature of the cold reservoir should be decreased and thus the temperature of hot reservoir be increased.

So, decrease the ratio of Tc/TH.

option (C)

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