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A bag contains 3 red marbles, 2 blue marbles and 6 green marbles. If two marbles are drawn out of the bag, what is the probability, to the nearest 10th of a percent, that both marbles drawn will be green?

Respuesta :

Answer:

P(A) = 20 %

Step-by-step explanation:

let S be the sample space of the experiment,

n(S) = 3 red marbles +2 blue marbles +6 green marbles

∴ n(S) = 11

let A be the event of getting both the marbles drawn as a green marbles

∴  n(A) = 2

∴ [tex]Probability(A)=\frac{n(A)}{n(S)} \\\\P(A) =\frac{2}{11} \\\\P(A) = 0.1818\\\\P(A) = 0.2[/tex]

P(A) = 0.2 × 100 = 20%

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