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the 7th grade and 8th grade students are selling tickets to the talent show. The 8th grade students have sold fifteen more than twice the number of tickets that the 7th grade students have. If They sold 486 tickets altogether, how many did the 8th grade students sell?

Respuesta :

Answer:

329 tickets

Step-by-step explanation:

  • x is the number the 8th graders sold and y is the number the 7th graders sold.
  • x+y=486 and x=2y + 15
  • use these equations to solve for x and y.
  • we know what x is so we can do this: (2y+15) +y =486
  • add like terms: 2y plus y is 3y:   3y + 15=486
  • next subtract 15 from both sides: 3y=471
  • divide both sides by 3: y=157.
  • 7 the grade sold 157 tickets
  • so 486 - 157 = 329

Not sure if this is right. But tell me if i'm wrong please. Hope this helped.

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