Answer:
0.661 m/s²
Explanation:
g = MG / r²
g = (1.31×10²² kg) (6.67×10⁻¹¹ m³/kg/s²) / (1.15×10⁶ m)²
g = 6.61×10⁻¹ m/s²
g = 0.661 m/s²
Gravity is a universal force of attraction that exists between all the objects having mass and energy. The gravity is directly proportional to mass and has an inverse relationship with radius.
The acceleration of a freely-falling object on Pluto is 0.661 m/s².
Given:
Mass of Pluto = 1.31×10²² kg
Radius of Pluto = 1.15×10⁶ m
Gravitational constant = 6.67×10⁻¹¹ m³/kg/s²
Formula for the gravitational force:
[tex]\text g &= \dfrac{\text{GM}}{r^2}[/tex]
Substituting the values in the above formula:
[tex]\text g = \dfrac{[1.31 \times 10^{22}] [6.67 \times 10 ^{-11}]}{[1.15 \times 10^6]^2}[/tex]
g = 0.661 m/s².
Therefore, the acceleration of a free-falling object will be 0.661 m/s².
To know more about gravity, refer to the following link:
https://brainly.com/question/4783082
