Answer:
3.5 × 10³ J
Explanation:
The heat required to raise the temperature of the beer can be calculated using the following expression.
Q = c × m × ΔT
where,
Q: heat
c: specific heat capacity
m: mass
ΔT: change in the temperature
The volume of the beer is 35 mL and its density 1.2 g/mL. The mass of the beer is:
mass = volume × density
35 mL × (1.2 g/mL) = 42 g
Q = c × m × ΔT
Q = (4.186 J/g.°C) × 42 g × (20]°C - 0°C) = 3.5 × 10³ J