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Romeo (77.0 kg) entertains Juliet (55.0 kg) by playing his guitar from the rear of their boat at rest in still water, 2.70 m away from Juliet, who is in the front of the boat. After the serenade, Juliet carefully moves to the rear of the boat (away from shore) to plant a kiss on Romeo’s cheek. How far does the 80.0-kg boat move toward the shore it is facing? 54. The vector position of a 3.50-g particle

Respuesta :

Answer:

The distance moved by the boat is 0.70 m.

Explanation:

Given that,

Mass of Romeo = 77.0 kg

Mass of Juliet = 55.0 kg

Distance = 2.70 m

Mass of boat = 80.0 kg

Let the distance moved by the boat is x.

as the center of mass will not change it's position

We need to calculate the distance moved by the boat

Using formula for distance

[tex]m_{r}x+m_{b}x-m_{j}(d-x)=0[/tex]

Put the value into the formula

[tex]77x+80x-55(2.70-x)=0[/tex]

[tex]212x-55\times2.70=0[/tex]

[tex]212x-148.5=0[/tex]

[tex]x=\dfrac{148.5}{212}[/tex]

[tex]x=0.70\ m[/tex]

Hence, The distance moved by the boat is 0.70 m.

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