The molecular formula of the compound is C₁₂H₆F₆.
Explanation:
The questions is:
Calculate the molecular formula for a compound with empirical formula C₂HF and molecular mass of 264.18 g/mole.
We know that by multiplying the empirical formula with an integer number we get the molecular formula. Taking this in account we do the following algorithm:
molar mass of empirical formula × n = 264.18
where n is the integer number
molar mass of empirical formula = molar mass of C × 2 + molar mass of H × 1 + molar mass of F × 1
molar mass of empirical formula = 12 × 2 + 1 × 1 + 19 × 1 = 44 g/mole
44 × n = 264.18
n = 264.18 / 44
n = 6
So the molecular formula of the compound is C₁₂H₆F₆.
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