Respuesta :
Answer:
After 15minutes, the water in test tube with the exposed Elodea plant will become colourless. While the solution with the wrapped Elodea plant will remain slightly yellow as it is.
Explanation:
The carbon dioxide introduced into each tube will lead to development of yellow coloration in the solutions. The exposed plant will use up more carbondioxide from the ones introduced in it's solution during the process of photosynthesis. This will disapprove the hypothesis formulated by the student, thereby returning the pH if the solution to it's neutral state. This will reverse the color to colourless nature of the distilled water. While the wrapped Elodea plant will not be able to use the available carbondioxide, therefore the solution will remain slightly acidic and the yellow color will remain.
She should expect to observe both colorless and yellow test tubes after the duration of 15 minutes.
After 15 minutes, the yellow colour of the open test tube vanished and becomes colorless due to escape of carbondioxide gas from the solution whereas the test tube which is wrapped in aluminium foil remains the same because no carbondioxide is escaped from the test tube due to the aluminium foil.
Carbondioxide gas can't dissolve in water so it tends to escape if no pressure is present on it so we can conclude that she expect to observe both colorless and yellow test tubes.
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