amurray2020
contestada

If f(x) = [tex]\sqrt{1/2x-10}[/tex] + 3, which inequality can be used to find the domain of f(x)?
A. [tex]\sqrt{1/2x}[/tex]≥0
B. [tex]\frac{1}{2} x[/tex]≥0
C. [tex]\frac{1}{2x}[/tex]-10≥0
D. [tex]\sqrt{1/2x-10} +3[/tex]≥0

Respuesta :

sqdancefan

Answer:

  [tex]\text{C.} \quad\dfrac{1}{2x}-10\ge 0[/tex]

Step-by-step explanation:

The contents of the radical must be non-negative. We cannot tell if the first term there is (1/2)x or 1/(2x). If the former, there is no correct answer choice. If the latter, the correct answer choice is ...

  [tex]\dfrac{1}{2x}-10\ge 0[/tex]

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