Answer:
Therefore the value of x = 10 units
Step-by-step explanation:
Let label the Triangles first,
Δ ABC a right triangle at ∠ A =90°
Δ ADB andΔ ADC a right triangle at ∠ D =90°
Such that
AD = x
BD = 50
CD = 2
∴ BC = BD + DC = 50 + 2 = 52
To Find:
x = ?
Solution:
In right triangle By Pythagoras Theorem,
[tex](\textrm{Hypotenuse})^{2} = (\textrm{Shorter leg})^{2}+(\textrm{Longer leg})^{2}[/tex]
In right triangle Δ ADB andΔ ADC By Pythagoras Theorem we will have,
AB² = BD² + AD²
AB² = 50² + x² ..................equation ( 1 )
and
AC² = DC² + AD²
AC² = 2² + x² ...................equation ( 2 )
Now in right triangle Δ ABC,
BC² = AB² + AC²
Equating equation (1 ) and ( 2 ) and the given value we get
52² = 50² + x² + 2² + x²
∴ 2x² = 2704 - 2504
∴ 2x² =200
∴ [tex]x^{2} =\frac{200}{2}\\\\\therefore x=\pm\sqrt{100} \\\\ \textrm{x cannot be negative}\\\therefore x= 10\ unit[/tex]
Therefore the value of x = 10 units
