The equation of line through given points in standard form is: x-2y = 3
Step-by-step explanation:
Given points are:
(x1,y1) = (-1,-2)
(x2,y2) = (3,0)
First of all, slope has to be found
[tex]m = \frac{y_2-y_1}{x_2-x_1}\\=\frac{0-(-2)}{3-(-1)}\\=\frac{0+2}{3+1}\\=\frac{2}{4}\\=\frac{1}{2}[/tex]
Equation of line in slope intercept form is:
[tex]y = mx+b[/tex]
Putting the value of slope
[tex]y =\frac{1}{2}x+b[/tex]
Putting the point (3,0) in equation
[tex]0 = \frac{1}{2}(3) +b\\0 = \frac{3}{2} +b\\b = -\frac{3}{2}[/tex]
Putting the value of b in the equation
[tex]y = \frac{1}{2}x-\frac{3}{2}[/tex]
Multiplying the equation by 2
[tex]2y = x - 3\\2y +3 = x-3+3\\2y+3 = x\\2y+3-2y = x-2y\\x-2y = 3[/tex]
Hence,
The equation of line through given points in standard form is: x-2y = 3
Keywords: Equation of line, slope
Learn more about equation of line at:
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