For this case we have that by definition, the slope of a line is given by:
[tex]m = \frac {y_ {2} -y_ {1}} {x_ {2} -x_ {1}}[/tex]
Where:
[tex](x_ {1}, y_ {1})[/tex]and[tex](x_ {2}, y_ {2})[/tex]are two points through which the line passes
According to the statement we have:
[tex](x_ {1}, y_ {1}): (- 8,4)\\(x_ {2}, y_ {2}) :( 3, -4)[/tex]
Substituting we have:
[tex]m = \frac {y_ {2} -y_ {1}} {x_ {2} -x_ {1}} = \frac {-4-4} {3 - (- 8)} = \frac {-8} {3 + 8} = \frac {-8} {11} = - \frac {8} {11}[/tex]
Thus, the slope of the line is:
[tex]m = - \frac {8} {11}[/tex]
Answer:
[tex]m = - \frac {8} {11}[/tex]
