Answer:
[tex]46 * 10^7[/tex] pfu/ml
Explanation:
Given -
Bacteriophage dilution [tex]= 0.1[/tex] ml
Volume of bacteria and plate with top agar [tex]= 0.3[/tex] ml
Number of plaques [tex]= 46[/tex] pfu
Dilution (d) [tex]= 10^{-6}[/tex]
Final concentration of phage stock is equal to
[tex]= \frac{pfu}{d*v}[/tex]
Where pfu is the count of plaques
d is the dilution and v is the volume
Substituting the given values, we get -
[tex]\frac{46}{10^{-6} * 10^{-1}} \\= 46 * 10^7[/tex] pfu/ml
