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Calculate the energy in joules to heat 828 g of
mercury from 37.0◦ C to 42.0◦ C. The specific
heat capacity of Hg(ℓ) is 0.139 J/g·
◦C.
Answer in units of joules.

Respuesta :

Answer:

There is 575.46 J of heat released

Explanation:

Step 1: Data given

Mass of mercury = 828 grams

Heat capacity of mercury = 0.139J/g°C

Initial temperature = 37.0°C

Final temperature = 42.0 °C

Step 2: Calculate heat released

Q = m*c*ΔT

⇒ Q =the heat released in Joule

⇒ m = the mass of mercury = 828 grams

⇒ c = the heat capacity of mercury = 0.139 J/g°C

 ⇒ ΔT = the change of temperature = T2 - T1 = 42.0 - 37.0 = 5.0 °C

Q = 828 g * 0.139 J/g°C * 5.0 °C

Q = 575.46 J

There is 575.46 J of heat released

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